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Lua Scripting • Re: Lua for conditional operators with strings as result.

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I can't test right now as I'm on the phone, but no, the error is exactly the same as the other cases, it only shows on first load and refresh without affecting the functionality.

However, I did test both with the earlier "sectionIndex" function and with the newer "SI" function, both giving the same results.

Maybe later, or tomorrow I can test a little bit more, since today's busy day.

One workaround that has come to my mind but I haven't tested, is using lua for the math that requires the use of the function. Something like:

Y=[&S:Math([&Meter[&S:SI()]:Y])]

Statistics: Posted by RicardoTM — Today, 2:42 am



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